3x^2+(8/x^2)=14

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Solution for 3x^2+(8/x^2)=14 equation: 



3x^2+(8/x^2)=14

We move all terms to the left:

3x^2+(8/x^2)-(14)=0



Domain of the equation: x^2)!=0

x!=0/1

x!=0

x∈R



We get rid of parentheses

3x^2+8/x^2-14=0

We multiply all the terms by the denominator


3x^2*x^2-14*x^2+8=0

We add all the numbers together, and all the variables

-14x^2+3x^2*x^2+8=0

Wy multiply elements

-14x^2+3x^4+8=0

We do not support expression: x^4

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